18x/(1+x^2)^2=36/10

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Solution for 18x/(1+x^2)^2=36/10 equation: 



18x/(1+x^2)^2=36/10

We move all terms to the left:

18x/(1+x^2)^2-(36/10)=0



Domain of the equation: (1+x^2)^2!=0

x∈R



We add all the numbers together, and all the variables

18x/(1+x^2)^2-(+36/10)=0

We get rid of parentheses

18x/(1+x^2)^2-36/10=0

We calculate fractions


180x/((1+x^2)^2*10)+(-36*(1+x^2)^2)/((1+x^2)^2*10)=0



We calculate terms in parentheses: +(-36*(1+x^2)^2)/((1+x^2)^2*10), so:

-36*(1+x^2)^2)/((1+x^2)^2*10

We multiply all the terms by the denominator


-36*(1+x^2)^2)

We multiply parentheses

-36x^2-36

Back to the equation:

+(-36x^2-36)



We get rid of parentheses

180x/((1+x^2)^2*10)-36x^2-36=0

We multiply all the terms by the denominator


-36x^2*((1+x^2)^2*10)-36*((1+x^2)^2*10)+180x=0

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